Home Forum Ask A Member Voltage Regulation, Re: 1959 Starflite

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  • #18503
    rvpapasso
    Participant

      The OMC generators use a toothed belt with corresponding tooth pulleys on the flywheel and generator. My best guess is to eliminate slippage since there is a very narrow range of adjustment to keep the belt tight.

      The solid state voltage regulator employs a solid state current limiter set for 10A. All three mechanical units and functions are replicated with solid state devices.

      Another detour…….

      In a mechanical regulator the cutout is not a relay as most people think. A relay will not work in this application and cause the battery to discharge into the battery at low generator output.

      The mechanical cutout is actually a mechanical diode that will only allow current to flow from the generator to the battery and block current flowing from the battery to the generator.

      These guys were clever how they achieved this with just two windings, a spring, electromagnetic core and contacts. It still amazes in both the simplicity and complexity in creating a mechanical diode.X

      #18536
      legendre
      Participant
        quote RVPapasso:

        The OMC generators use a toothed belt with corresponding tooth pulleys on the flywheel and generator. My best guess is to eliminate slippage since there is a very narrow range of adjustment to keep the belt tight.

        The solid state voltage regulator employs a solid state current limiter set for 10A. All three mechanical units and functions are replicated with solid state devices.

        Interesting, thank you.

        quote :

        In a mechanical regulator the cutout is not a relay as most people think. A relay will not work in this application and cause the battery to discharge into the battery at low generator output.

        "battery to discharge into the battery" – must be a typo, but I can’t tell for certain what you actually meant. Perhaps "battery discharge into the generator"?

        quote :

        The mechanical cutout is actually a mechanical diode that will only allow current to flow from the generator to the battery and block current flowing from the battery to the generator.

        I’m totally unfamiliar with this one.. can you explain a bit more or point me to a resource? Googling for ‘mechanical diode’ mainly brings up references to sprag clutches and the like, as used in some electrical starter drives. My understanding was that the cutout was an NO relay that closed, connecting the generator to the battery, when the armature voltage exceeded a certain lower limit.

        #18560
        rvpapasso
        Participant

          You are correct with my typo, "battery to discharge into the battery", "battery discharge into the generator" is correct. I have been replying on my iPhone but too many typos forced me to use my desktop with a real keyboard, maybe less typos!

          I don’t know a good internet source for the information presented below. Typical with the internet there is a lot of misinformation and people’s “best guess” at how stuff works. My knowledge on this subject comes from vintage manuals for cars and motorcycles when the technology was first introduced. That information coupled with my background as an EE (Electronic Engineer) helped me to understand it.

          A simple NO (normally open) relay typically closes at 80% of the designed voltage and opens at 20%. For simplicity assume a 10V system. The relay would close when the generator gets to 8V. If the battery is at 10V then the battery would immediately discharge into the generator since the generator is at a lower voltage.

          Even if you designed the upper end of the NO relay to close at 10V you still have the 20% end to deal with before the NO relay would open. That means once the contacts close connecting the generator and battery the contacts are not going to open until both the generator and battery are at 2V. As you can deduce this is not going to work to keep a battery charged.

          The cutout has two separate windings, let’s call them a voltage winding and current winding. The voltage winding goes from the generator output to ground. Its function is to close the contacts when the generator voltage reaches the designed voltage. The second winding, the current winding, carries the current from the generator to the contacts and when the contacts are closed, to the battery.

          Here is how it works assuming a 10V system and the battery is at 9V. When the generator output gets to 10V the voltage winding will cause the contacts to close. Let’s assume this polarizes the cutout core as magnetic North. The magnetic field overcomes the spring pressure holding the contacts open and the contacts will close.

          When the contacts close current will flow thru the current winding to the battery since the generator output is higher than the battery. The current winding also magnetically polarizes the cutout core as North reinforcing the closing of the contacts.

          At this point the voltage does not matter as long as current is flowing thru the current coil from the generator to the battery and the contacts will stay closed. Even if the load of a low battery pulls the generator down to 5V the current flowing thru the current winding will maintain a magnetic field and keep the contacts closed.

          When the generator voltage gets lower than the battery the current will reverse directions in the current coil and flow from the battery to the generator. A reversal of current thru the current winding also changes the magnetic polarity of the current coil to South. At some magic point the South magnetic polarity thru the current winding will equal the North polarity of the voltage coil. When this occurs the magnetic forces cancel each other and the spring will pull the contacts open disconnecting the generator and battery.

          When the battery is disconnected from the generator the current flowing thru current winding stops. With the load of the battery removed the generator output may increase back to 10V causing the contacts to close. If this happens the above cycle will be repeated, i.e. keeping the contacts closed if current flows from the generator to the battery or opening the contacts if current flows from the battery to the generator. This will repeat many cycles per second until the generator output gets below the set voltage of the voltage coil and the contacts will no longer close. This of course causes arcing and pitting of the contact points and they need periodic cleaning.

          Hence the simplicity and complexity of the cutout to act as a mechanical diode!

          #18622
          frankr
          Participant

            US Member

            Boy, that certainly was an educated and thorough explanation, probably true. I haven’t read it and absorbed it all yet. Can’t we just say the cut-out relay disconnects the generator from the battery when it isn’t putting out enough voltage to charge the battery? Yes, if it were not disconnected under such a situation, the battery would discharge through the generator. And it also is why the generator doesn’t charge the battery at all until it is running fast enough to close the relay. Think relay and not diode and the mystery goes away.

            The current regulator section is what limits the maximum generator output in Amps (10).

            The voltage regulator section is what controls the charging voltage (about 14.5 Volts)

            #18640
            legendre
            Participant

              @RVPapasso

              Very good explanation.. and yes, I’m familiar with that type of solenoid. It’s a two-winding coil with the standard pull-in winding and a second ‘bucking’ winding that swiftly cancels the flux from the first, when the current reverses. I don’t recall the proper term for this design.

              I’ve seen this sort of design in other industrial controls where relay hysteresis is an issue, as you point out that it would be in a mechanical reg cutout. But I’d never thought about the fact that they were used in this application.

              Nice bit of education for all, thanks for taking the time.

              quote FrankR:

              Can’t we just say the cut-out relay disconnects the generator from the battery when it isn’t putting out enough voltage to charge the battery?

              Yes, that’s the gist of it. It’s just that a conventional relay isn’t up to the task, for as RVPapasso points out, it has too much hysteresis.

              quote :

              Yes, if it were not disconnected under such a situation, the battery would discharge through the generator. And it also is why the generator doesn’t charge the battery at all until it is running fast enough to close the relay. Think relay and not diode and the mystery goes away.

              The current regulator section is what limits the maximum generator output in Amps (10).

              The voltage regulator section is what controls the charging voltage (about 14.5 Volts)

              Correct again, on all counts.

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